JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Easy

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Analyzing +4 | -1

The point in the interval

\left[ {0,\;2\pi } \right]

where

f\left( x \right) = {e^x}\sin x

has maximum slope is

View answer and explanation

Correct option: B

\frac{\pi }{2}

Option B (

\frac{\pi }{2}

) is correct because the maximum slope occurs where the second derivative is zero and the third derivative is negative.

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a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z