JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

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Application +4 | -1

x\mathrm{ }dy = y\left( {dx + y\mathrm{ }dy} \right),y\left( 1 \right) = 1

and

y\left( x \right) > 0

, then

y\left( { - 3} \right)

is equal to

View answer and explanation

Correct option: A

Option A, 3, is the correct answer because solving the differential equation and applying the initial condition leads to y(-3) = 3.

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\lim \limits_{{x \rightarrow \infty}} y(t)