JEE MATHEMATICS MCQ: TANGENTS & NORMALS

1 Medium

1 of 1

Application +4 | -1

\int\limits_{{\pi / 2}}^x \sqrt{\left(3-2 \sin ^2 t\right)}+\int\limits_{0}^y \cos t d t=0

, then

\left(\frac{d y}{d x}\right)_{\pi, \pi}

is equal to

View answer and explanation

Correct option: C

\sqrt{3}

Option C (

\sqrt{3}

) is correct because after differentiating the given equation and substituting the given point, we find the derivative to be

\sqrt{3}

More Questions from TANGENTS & NORMALS

Practice All Chapter MCQs →

a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z