In a lime kiln, to get higher yield of ${\rm{C}}{{\rm{O}}_2}$, the measure that can be taken is

To pump out ${\rm{C}}{{\rm{O}}_2}$

To add more ${\rm{CaC}}{{\rm{O}}_3}$

NEET UG CHEMISTRY MCQ: Equilibrium

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In a lime kiln, to get higher yield of

\mathrm{C}{\mathrm{O}_2}

, the measure that can be taken is

View answer and explanation

Correct option: D

To pump out

\mathrm{C}{\mathrm{O}_2}

Option D is correct because removing CO2 shifts the equilibrium to the right, increasing the yield of CO2 according to Le Chatelier's principle.

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Mg{(HC{O_3})_2}

MgC{O_3}

Mg{(OH)_2}

MgC{O_3}

K_{\mathrm{P}}

\mathrm{CaCO}_3

4.5 \times 10^{-2}

\mathrm{C}(\mathrm{s})+\mathrm{CO}_2(\mathrm{g}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g}),

K_{\mathrm{P}}

2.0 \mathrm{~atm}.

\mathrm{CaO}

\mathrm{CaCO}_3

+

\leftrightharpoons

\mathrm{PC}{\mathrm{l}_5}\leftrightharpoons\mathrm{PC}{\mathrm{l}_3} + \mathrm{C}{\mathrm{l}_2}

{K_{\mathrm{eq}}} = 0.41

\mathrm{p}{K_a}