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JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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Application +4 | -1
In △ABC\triangle A B C, if sin⁡2A+sin⁡2B=sin⁡2C\sin ^{2} A+\sin ^{2} B=\sin ^{2} C, then ∠C=\angle C=
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Correct option: D
90∘90^{\circ}
Option D (90°) is correct because the given equation sin2(A) + sin2(B) = sin2(C) implies a2 + b2 = c2, which is the Pythagorean theorem, indicating that angle C is 90 degrees.

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