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JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

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Analyzing +4 | -1
If the curve y=y(x)y = y(x) is the solution of the differential equation
2(x2+x5/4)dy−y(x+x1/4)dx=2x9/4dx,  x>02({x^2} + {x^{5/4}})dy - y(x + {x^{1/4}})\mathrm{ }dx = 2{x^{9/4}}dx,\,\,x > 0 which passes through the point (1,  1−43log⁡e2)\left( {1,\,\,1 - \frac{4}{3}{{\log }_e}2} \right),then the value of y(16)y(16) is equal to
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Correct option: C
4(313−83log⁡e3)4\left( {\frac{{31}}{3} - \frac{8}{3}{{\log }_e}3} \right)
Option C (4\left( {\frac{{31}}{3} - \frac{8}{3}{{{\log }_e}3} \right)4\left( {\frac{{31}}{3} - \frac{8}{3}{{{\log }_e}3} \right)) is correct because it is the result of solving the given differential equation and applying the provided initial condition to find y(16).

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