JEE MATHEMATICS MCQ: TANGENTS & NORMALS

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Analyzing +4 | -1

The tangent to the curve

y = {x^3} - 6{x^2} + 9x + 4,\;0 \le x \le 5

has maximum slope at

x

which is equal to

View answer and explanation

Correct option: D

None of these

Option C (Makes an acute angle with the

x

-axis) is correct because the derivative is always positive, indicating an acute angle.

More Questions from TANGENTS & NORMALS

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a

y=x^3-a x

x^2 y=1-y

x y=1-y

C

y^3-3 x y+2=0

H

\mathrm{C}

x

V

C

y

y-e^{x y}+x=0

y = f\left( x \right)

x

x = a\left( {\theta - \sin \theta } \right),\;y = a\left( {1 + \cos \theta } \right)

\theta = \left( {2k + 1} \right)\pi ,\;k \in Z