Question

The integral $\int \frac{\left(x^8-x^2ight) d x}{\left(x^{12}+3 x^6+1ight) 	an ^{-1}\left(x^3+\frac{1}{x^3}ight)}$ is equal to

Accepted Answer

$\frac{1}{3} \ln \left|\left(	an ^{-1}\left(x^3+\frac{1}{x^3}ight)ight)ight|+c$

Answer

$\ln \left|\left(	an ^{-1}\left(x^3+\frac{1}{x^3}ight)ight)ight|+c$

Answer

$\frac{1}{6}\ln \left| {\left( {{{	an }^{ - 1}}\left( {{x^3} + \frac{1}{{{x^3}}}} ight)} ight)} ight| + c$

Answer

$\frac{1}{9}\ln \left| {\left( {{{	an }^{ - 1}}\left( {{x^3} + \frac{1}{{{x^3}}}} ight)} ight)} ight| + c$

JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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