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JEE PHYSICS MCQ: KINETIC THEORY OF GASES

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For a gas, if the ratio of specific heats at constant pressure and constant volume is γ\gamma, then the value of degrees of freedom is
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Correct option: D
2γ−1\frac{2}{\gamma-1}
Option D (2γ−1\frac{2}{\gamma-1}) is correct because the degrees of freedom nn are related to the ratio of specific heats γ\gamma by the formula γ=1+2n\gamma = 1 + \frac{2}{n}, which can be rearranged to n=2γ−1n = \frac{2}{\gamma-1}.

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