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JEE PHYSICS MCQ: GRAVITATION

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The ratio of gravitational force and electrostatic repulsive force between two electrons is approximately (gravitational constant

=6.7 \times 10^{-11} \mathrm{Nm}^2 / \mathrm{kg}^2,

mass of an electron

=9.1 \times 10^{-31} \mathrm{~kg},

charge on an electron

=1.6 \times 10^{-19} \mathrm{C}

)

View answer and explanation

Correct option: C

24 \times 10^{-44}

Option C (

24 \times 10^{-44}

) is correct because it is calculated by dividing the gravitational force by the electrostatic force between two electrons.

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