Domain of the function $ f(x)=\sin ^{-1}\left(1+3 x+2 x^{2}\right) $ is

$ \left(-\infty, \frac{-1}{2}\right) \cup(2, \infty) $

JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

Domain of the function

f(x)=\sin ^{-1}\left(1+3 x+2 x^{2}\right)

View answer and explanation

Correct option: C

\left[-\frac{3}{2}, 0\right]

Option C ([-3/2, 0]) is correct because the domain requires the argument of the arcsin function to be between -1 and 1.

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