If the domain of the function $f(x)=\sqrt{3 \cos ^{-1}(4 x)-\pi}$ is $[a, b]$, then the value of $(4 a+64 b)$ is

JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

If the domain of the function

f(x)=\sqrt{3 \cos ^{-1}(4 x)-\pi}

[a, b]

, then the value of

(4 a+64 b)

View answer and explanation

Correct option: A

Option A (9) is correct because using the properties of binomial expansion and the given condition y=12x, we can solve for n.

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f:(-\infty, 2] \longrightarrow(-\infty, 4]

f(x)=x(4-x)

f^{-1}(x)

g(f(x))=|\sin x|

f(g(x))=(\sin \sqrt{x})^2

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}