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JEE PHYSICS MCQ: OSCILLATIONS

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The motion of a particle is expressed by the equation acc. a

=-

bx where

\mathrm{x}

is displacement from equilibrium position and

b

is constant. What is the periodic time?

View answer and explanation

Correct option: B

\frac{2 \pi}{\sqrt{b}}

Option B (

\frac{2 \pi}{\sqrt{b}}

) is correct because the periodic time is calculated using the formula

T = \frac{2\pi}{\omega}

, where

\omega = \sqrt{b}

from the given acceleration equation.

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