If $x=a \cos ^2 \theta \sin \theta$ and $y=$ a $\sin ^2 \theta \cos \theta$, then $\left(x^2+y^2\right)^3$ is

JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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Application +4 | -1

x=a \cos ^2 \theta \sin \theta

and

y=

\sin ^2 \theta \cos \theta

, then

\left(x^2+y^2\right)^3

View answer and explanation

Correct option: B

a^2 x^2 y^2

Option B (

a^2 x^2 y^2

) is correct because by substituting the given expressions for x and y, and simplifying, we find that

(x^2+y^2)^3 = a^2 x^2 y^2

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\triangle A B C

C

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\sin ^2(A / 2)+\sin ^2(B / 2)-\sin ^2(C / 2)=