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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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Given b=2,c=3,∠A=30∘b=2, c=\sqrt{3}, \angle A=30^{\circ}. Then the in-radius of △ABC\triangle A B C is
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Correct option: A
3−12\frac{\sqrt{3}-1}{2}
Option A (3−12\frac{\sqrt{3}-1}{2}) is correct because the in-radius can be calculated using the formula r=Δsr = \frac{\Delta}{s} after finding the area and semi-perimeter.

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