Question

Given,

\mathrm{KOH}(\mathrm{aq})+\mathrm{HCl}(\mathrm{aq}) \longrightarrow \mathrm{KCl}(\mathrm{aq})+\mathrm{H}_2 \mathrm{O}(l); \Delta H=-57.3 \mathrm{~kJ} \mathrm{~mol}^{-1} \ldots (i)

\mathrm{H}_2(\mathrm{~g})+\frac{1}{2} \mathrm{O}_2(\mathrm{~g}) \longrightarrow \mathrm{H}_2 \mathrm{O}(\mathrm{l}); \Delta \mathrm{H}=-286.2 \mathrm{~kJ} \mathrm{~mol}^{-1} \ldots.....(ii)

\frac{1}{2} \mathrm{H}_2(\mathrm{~g})+\frac{1}{2} \mathrm{Cl}_2(\mathrm{~g}) \xrightarrow{A q} \mathrm{HCl}(\mathrm{aq}); \Delta H=-164.4 \mathrm{~kJ} \mathrm{~mol}^{-1} \ldots(\mathrm{iii)}

\mathrm{K}(\mathrm{s})+\frac{1}{2} \mathrm{O}_2(\mathrm{~g})+\frac{1}{2} \mathrm{H}_2(\mathrm{~g})+\mathrm{aq} \longrightarrow \mathrm{KOH}(\mathrm{aq}) ; \Delta H=-487.4 \mathrm{~kJ} \mathrm{~mol}^{-1} \ldots(\mathrm{iv})

\mathrm{KCl}(\mathrm{s})+\mathrm{aq} \longrightarrow \mathrm{KCl}(\mathrm{aq}); \Delta H=+18.4 \mathrm{~kJ} \mathrm{~mol}{ }^{-1}

.....(v)

Heat of formation of

\mathrm{KCl}

will be

Accepted Answer

$-441.3 \mathrm{~kJ} \mathrm{~mol}^{-1}$

Answer

$-44.13 \mathrm{~kJ} \mathrm{~mol}^{-1}$

Answer

$+441.3 \mathrm{~kJ} \mathrm{~mol}^{-1}$

Answer

$-4413 \mathrm{~kJ} \mathrm{~mol}^{-1}$

NEET UG CHEMISTRY MCQ: THERMODYNAMICS

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