JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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{\log _{\tan 30^\circ }}\left( {\frac{{2{{\left| z \right|}^2} + 2\left| z \right| - 3}}{{\left| z \right| + 1}}} \right) < - 2,

then

View answer and explanation

Correct option: C

\left| z \right| > 2

Option C (

\left| z \right| > 2

) is correct because solving the logarithmic inequality leads to the condition that the magnitude of z is greater than 2.

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