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JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1
Let f(x)=ax+b\mathrm{f}(\mathrm{x})=\mathrm{ax}+\mathrm{b} is a function such that f−1(2)=3,f−1(−3)=6\mathrm{f}^{-1}(2)=3, \mathrm{f}^{-1}(-3)=6, where f−1(x)\mathrm{f}^{-1}(\mathrm{x}) is the inverse of function f\mathrm{f} then a+b\mathrm{a}+\mathrm{b} is equal to
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Correct option: B
163\frac{16}{3}
Option B (163\frac{16}{3}) is correct because by using the given inverse function values, we can find the values of aa and bb and then calculate a+ba+b.

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