JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Hard

1 of 1

Analyzing +4 | -1

The number of all possible triplets

\left( {{a_1},\,\,{a_2},\,{a_3}} \right)

such that

{a_1} + {a_2}\,\,\cos \,\,2x + {a_3}{\sin ^2}x = 0

for all

x

View answer and explanation

Correct option: D

None of these

The correct answer is None of these because there are infinitely many triplets that satisfy the given condition.

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