JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

a, b, x, y \in \mathbf{R}, \omega \neq 1

, is a cube root of unity and

(a+b \omega)^7=x+y \omega

, then

(b+a \omega)^7

equals

View answer and explanation

Correct option: A

y+x \omega

Option A (

y+x \omega

) is correct because by taking the conjugate and manipulating the expression using the properties of cube roots of unity, we find that

(b + a\omega)^7 = y + x\omega

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