Domain of $ f(x)=\left(x^{2}-1\right)^{-1 / 2} $ is

JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

Domain of

f(x)=\left(x^{2}-1\right)^{-1 / 2}

View answer and explanation

Correct option: A

(-\infty,-1) \cup(1, \infty)

Option A ((-∞,-1) ∪(1, ∞)) is correct because the domain requires the expression inside the square root to be positive and the denominator to be non-zero.

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