JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Application +4 | -1

The three angular points of a triangle are given by

Z=\alpha, Z=\beta, Z=\gamma

, where

\alpha, \beta, \gamma

are complex numbers, then the perpendicular from the angular point

Z=\alpha

to opposite side is given by the equation :

View answer and explanation

Correct option: B

\operatorname{Re}\left(\frac{Z-\alpha}{\beta-\gamma}\right)=0

Option B (Re(

\frac{{Z-\alpha}}{{\beta-\gamma}}

)=0) is correct because the perpendicularity condition implies that the argument of the complex number (Z-α)/(β-γ) is π/2, making its real part zero.

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