Question

A solution containing 2.675 g of ${\rm{CoC}}{{\rm{l}}_3}{\rm{\;}}.6{\rm{N}}{{\rm{H}}_3}$ (molar mass $ = 267.5\,\,{\rm{ }}g\,\,{\rm{ mo}}{{\rm{l}}^{ - 1}}$) is passed through a cation exchanger. The chloride ions obtained in solution were treated with excess of ${\rm{AgN}}{{\rm{O}}_3}$ to give 4.78 g of ${\rm{AgCl}}$ (molar mass $ = 143.5\,\,{\rm{g}}\,\,{\rm{mo}}{{\rm{l}}^{{\rm{ - 1}}}}$). The formula of the complex is (Atomic mass of ${\rm{Ag}}\,{\rm{ = }}\,{\rm{108\,\, u}}$)

Accepted Answer

$\left[ {{\rm{Co}}{{\left( {{\rm{N}}{{\rm{H}}_3}} \right)}_6}} \right]{\rm{C}}{{\rm{l}}_3}$

Answer

$\left[ {{\rm{CoC}}{{\rm{l}}_2}{{\left( {{\rm{N}}{{\rm{H}}_3}} \right)}_4}} \right]{\rm{Cl}}$

Answer

$\left[ {{\rm{CoC}}{{\rm{l}}_3}{{\left( {{\rm{N}}{{\rm{H}}_3}} \right)}_3}} \right]$

Answer

$\left[ {{\rm{CoCl}}{{\left( {{\rm{N}}{{\rm{H}}_3}} \right)}_5}} \right]{\rm{C}}{{\rm{l}}_2}$

NEET UG CHEMISTRY MCQ: CO-ORDINATION COMPOUNDS

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