JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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Application +4 | -1

A particle moves in a circle of radius 25 cm at two revolutions per second. The acceleration of the particle in

m/{s^2}

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Correct option: C

4{\pi ^2}

Option C (

4{\pi ^2}

) is correct because it is the centripetal acceleration calculated using the given radius and angular velocity.

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\mathrm{AB}

\mathrm{L}

\mu(x)=a+\frac{b x}{L}

x

\mathrm{A}

\mathrm{CM}

\left(\frac{7}{12}\right) \mathrm{L}

\mathrm{A}

\mathrm{b}

1.0 \mathrm{~g}

8 \mathrm{~cm}

\omega = {t^4} + 2{t^3}

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)