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JEE PHYSICS MCQ: GRAVITATION

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A body of mass mm is taken from earth surface to the height h\mathrm{h} equal to radius of earth, the increase in potential energy will be
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Correct option: B
12mgR\frac{1}{2} \mathrm{mgR}
Option B (12mgR\frac{1}{2} \mathrm{mgR}) is correct because the change in potential energy is calculated using the formula ΔU=mgh1+h/R\Delta U = \frac{mgh}{1 + h/R} with h = R.

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