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JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Analyzing +4 | -1
The value of the expression
(2−ω)(2−ω2)+2(3−ω)(3−ω2)+.……+.…+(n−1)(n−ω)(n−ω2)\left( {2 - \omega } \right)\left( {2 - {\omega ^2}} \right) + 2\left( {3 - \omega } \right)\left( {3 - {\omega ^2}} \right) + . \ldots \ldots + . \ldots + \left( {n - 1} \right)\left( {n - \omega } \right)\left( {n - {\omega ^2}} \right)
Where ω\omega is an imaginary cube root of unit is
View answer and explanation
Correct option: A
(n−1)n(n2+3n+4)/4\left( {n - 1} \right)n\left( {{n^2} + 3n + 4} \right)/4
Option A is correct because the expression simplifies to (n−1)n(n2+3n+4)4\frac{{(n - 1)n(n^2 + 3n + 4)}}{{4}} after expanding and summing the terms using the properties of cube roots of unity.

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