JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

1 Easy

1 of 1

Application +4 | -1

In a

\triangle \mathrm{ABC}, \frac{\mathrm{a}}{\mathrm{b}}=2+\sqrt{3}

and

\angle \mathrm{C}=60^{\circ}

. Then the ordered pair

(\angle \mathrm{A}, \angle \mathrm{B})

is equal to :

View answer and explanation

Correct option: B

\left(105^{\circ}, 15^{\circ}\right)

Option B ((105°, 15°)) is correct because using the sine rule and the given ratio, the angles A and B can be found to be 105° and 15° respectively.

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2 s