JEE MATHEMATICS MCQ: FUNCTIONS

1 Medium

1 of 1

Application +4 | -1

Given

f(g(x))=1+x-2 x^2+5 x^3

and

f(x)=1+3 x \, \forall \, x \in R

, then the value of

3 g(1)

is equal to

View answer and explanation

Correct option: C

The correct answer is C (4) because by substituting f(x) into f(g(x)) and solving for g(x), then evaluating 3g(1) yields 4.

More Questions from FUNCTIONS

Practice All Chapter MCQs →

f:(-\infty, 2] \longrightarrow(-\infty, 4]

f(x)=x(4-x)

f^{-1}(x)

g(f(x))=|\sin x|

f(g(x))=(\sin \sqrt{x})^2

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}