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JEE MATHEMATICS MCQ: MEAN VALUES THEOREM

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Application +4 | -1
If the function f(x)=ax3+bx2+11x−6f\left( x \right) = a{x^3} + b{x^2} + 11x - 6 satisfies the condition of Rolle’s theorem in [1, 3] and f′(2+13)=0f'\left( {2 + \frac{1}{{\sqrt 3 }}} \right) = 0, then the values of a,ba,b are respectively
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Correct option: C
1,−61, - 6
Option C (1,−61, - 6) is correct because these values of a and b satisfy the conditions of Rolle's theorem and the given derivative condition.

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