NEET UG PHYSICS MCQ: MECHANICAL PROPERTIES OF SOLIDS

1 Easy

1 of 1

Application +4 | -1

Young's modulus of rubber is

10^4 \mathrm{~N} / \mathrm{m}^2

and area of cross-section is

2 \mathrm{~cm}^2

. If force of

2 \times 10^5

dynes is applied along its length, then its initial length

L

becomes

View answer and explanation

Correct option: C

Option C (2L) is correct because the final length is twice the initial length based on the given Young's modulus, area, and force.

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