A gas expands under constant pressure P from volume ${V_1}$ to ${V_2}$. The work done by the gas is

$P\left( {{V_1} - {V_2}} \right)$

$P\left( {V_1^\gamma - V_2^\gamma } \right)$

$P\frac{{{V_1}{V_2}}}{{{V_2} - {V_1}}}$

JEE PHYSICS MCQ: THERMODYNAMICS

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Understanding +4 | -1

A gas expands under constant pressure P from volume

{V_1}

{V_2}

. The work done by the gas is

View answer and explanation

Correct option: A

P\left( {{V_2} - {V_1}} \right)

Option A (

P(V_2 - V_1)

) is correct because the work done by a gas expanding under constant pressure is given by this formula.