NEET UG PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

1 Hard

1 of 1

Application +4 | -1

A charged particle

q_1

is at position

(2,-1,3)

. The electrostatic force on another charge particle

q_2

(0,0,0)

View answer and explanation

Correct option: D

\frac{q_1 q_2}{56 \sqrt{14} \pi \varepsilon_0}(-2 \hat{i}+\hat{j}-3 \hat{k})

Option D is correct because it accurately calculates the electrostatic force vector using Coulomb's law in vector form, considering the position vectors of the charges.

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The ratio of magnitude of electric displacement (D) and electric field (E) is Gauss’s Law is valid for In hydrogen like system the ratio of coulombian force and gravitational force between an electron and a proton is in the order of: Statement-1:

\overrightarrow{{E}}

in outside velocity of a conductor depends only on the local charge density

\alpha

.
Statement-2:

\overrightarrow{{E}}

in outside vicinity of a conductor is given by

\frac{\sigma}{\varepsilon_0}

. Two charges each of 1 coulomb are at a distance 1

km

apart the force between them is

P \times 10^3

then value of

{P}

is Electric field due to point charge depends on distance

r