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JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

1 Easy

1 of 1

Application +4 | -1

Two charges of

5 Q

and

-2 Q

are situated at the points

(3 a, 0)

and

(-5 a, 0)

respectively. The electric flux through a sphere of radius '

4 a

' having center at origin is

View answer and explanation

Correct option: D

\frac{5 Q}{\varepsilon_0}

Option D (

\frac{5 Q}{\varepsilon_0}

) is correct because it applies Gauss's law to find the electric flux through the sphere, considering only the charge enclosed within the sphere.

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