In a $\Delta \,ABC$ if $a = 5,\,\,b = 4$ and $\tan \frac{C}{2} = \frac{{\sqrt 7 }}{3}$, then $c = $

JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

1 Medium

1 of 1

Application +4 | -1

In a

\Delta \,ABC

a = 5,\,\,b = 4

and

\tan \frac{C}{2} = \frac{{\sqrt 7 }}{3}

, then

c =

View answer and explanation

Correct option: C

Option C (6) is correct because by using the Law of Cosines and the given value of

\tan \frac{C}{2}

, we can find the value of c.

Practice All Chapter MCQs →

{p_1},{p_2},{p_3}

\Delta \;ABC

A,B,C

\Delta

p_1^{ - 2} + p_2^{ - 2} + p_3^{ - 2}

5k,\;6k,\;5k

k

\Delta \,ABC

a = \left( {b - c} \right)\sec \theta

\frac{{2\,\sqrt {bc} }}{{b - c}}\,\,\sin \,\,\frac{A}{2} =

\Delta \;ABC,\frac{{b + c}}{a}

\Delta = {a^2} - {\left( {b - c} \right)^2}

\Delta

\Delta \;ABC

\tan A

A

2 s