The solution of $\log \left( {\frac{{dy}}{{dx}}} \right) = ax + by$ is

$\frac{{{e^{ - by}}}}{a} = \frac{{{e^{ax}}}}{b} + c$

JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

1 Easy

1 of 1

Application +4 | -1

The solution of

\log \left( {\frac{{dy}}{{dx}}} \right) = ax + by

View answer and explanation

Correct option: B

\frac{{{e^{ - by}}}}{{ - b}} = \frac{{{e^{ax}}}}{a} + c

Option B (

\frac{{{e^{ - by}}}}{{ - b}} = \frac{{{e^{ax}}}}{a} + c

) is correct because it is the solution obtained by separating variables and integrating the given differential equation.

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