JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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Analyzing +4 | -1

A large tray of mass

{M}

has in it a cubical block of ice of mass

{m}

and edge length

{L}

. The ice starts melting. The shift in the height of centre of mass of system (ice + tray) is

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Correct option: C

\frac{1}{2} \frac{{mL}}{({m}+{M})}

; downward

Option C (mL/(2(m+M)); downward) is correct because the shift in the center of mass is calculated considering the ice melting and the change in height of the center of mass.

More Questions from SYSTEM OF PARTICLES

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It is easier for a swimmer jumping into water from a height to describe a loop in the air by A uniform thin rod

\mathrm{AB}

of length

\mathrm{L}

has linear mass density

\mu(x)=a+\frac{b x}{L}

, where

x

is measured from

\mathrm{A}

. If the

\mathrm{CM}

of the rod lies at a distance of

\left(\frac{7}{12}\right) \mathrm{L}

from

\mathrm{A}

, then a and

\mathrm{b}

1.0 \mathrm{~g}

is rotating in a circle of diameter

8 \mathrm{~cm}

. Its moment of inertia will be The angular velocity of a particle is given by

\omega = {t^4} + 2{t^3}

then its angular acceleration of the particle at

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)