JEE MATHEMATICS MCQ: 2D GEOMETRY SYSTEM

1 Medium

1 of 1

Application +4 | -1

Without changing the direction of coordinate axes, origin is transferred to

(h, k)

, so that the linear (one degree) terms in the equation

x^{2}+y^{2}-4 x+6 y-7=0

are eliminated. Then the point

(h, k)

View answer and explanation

Correct option: C

(2,-3)

Option C (

(2,-3)

) is correct because substituting

x=x'+h

and

y=y'+k

into the equation and setting the coefficients of

x'

and

y'

to zero eliminates the linear terms, leading to

h=2

and

k=-3

More Questions from 2D GEOMETRY SYSTEM

Practice All Chapter MCQs →

\alpha

(\alpha, 2 \alpha)

\Delta A B C

A(0,2), B(2,0)

C(4,4)

P

2 P A=3 P B

A

(0,0)

B

(4,-3)

(1, \sqrt{3}),(0,0)

(2,0)

(1,5),(-3,1) \,\&\,(-2,1)

9 x^2-16 y^2-18 x+32 y-23

=0

25 x^2+9 y^2-50 x-18 y+33=0

(0,0)(3,0)

(0,4)