From separate solutions of four sodium salts ${\rm{Na}}W,{\rm{Na}}X,{\rm{Na}}Y\;and\;{\rm{Na}}Z$ had ${\rm{pH}}\;\;7.0,9.0,10.0\;and\;11.0$ respectively. When each solution was $0.1\;M$, the strongest acid is:

NEET UG CHEMISTRY MCQ: Equilibrium

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Analyzing +4 | -1

From separate solutions of four sodium salts

\mathrm{Na}W,\mathrm{Na}X,\mathrm{Na}Y\;and\;\mathrm{Na}Z

had

\mathrm{pH}\;\;7.0,9.0,10.0\;and\;11.0

respectively. When each solution was

0.1\;M

, the strongest acid is:

View answer and explanation

Correct option: A

HW

Option A (

HW

) is correct because the sodium salt with the lowest pH (pH 7.0) corresponds to the strongest acid.

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Mg{(HC{O_3})_2}

MgC{O_3}

Mg{(OH)_2}

MgC{O_3}

K_{\mathrm{P}}

\mathrm{CaCO}_3

4.5 \times 10^{-2}

\mathrm{C}(\mathrm{s})+\mathrm{CO}_2(\mathrm{g}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g}),

K_{\mathrm{P}}

2.0 \mathrm{~atm}.

\mathrm{CaO}

\mathrm{CaCO}_3

+

\leftrightharpoons

\mathrm{PC}{\mathrm{l}_5}\leftrightharpoons\mathrm{PC}{\mathrm{l}_3} + \mathrm{C}{\mathrm{l}_2}

{K_{\mathrm{eq}}} = 0.41

\mathrm{p}{K_a}