JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

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Analyzing +4 | -1

The degree of the differential equation satisfying the relation

\sqrt {1 + {x^2}} + \sqrt {1 + {y^2}} = \lambda \left( {x\sqrt {1 + {y^2}} - y\sqrt {1 + {x^2}} } \right)

, is

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Correct option: A

Option A (1) is correct because after simplifying the given relation and differentiating, the resulting differential equation is of degree 1.

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