JEE MATHEMATICS MCQ: FUNCTIONS

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Analyzing +4 | -1

If { } denotes the fractional part of

x

, the range of the function

f(x)=\sqrt{\{x\}^2-2\{x\}}

View answer and explanation

Correct option: D

\{0\}

Option C (

\pi

) is correct because by differentiating the given relation implicitly and substituting x=0, the second derivative y''(0) is found to be equal to

\pi

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f:(-\infty, 2] \longrightarrow(-\infty, 4]

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f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}