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JEE MATHEMATICS MCQ: STRAIGHT LINES

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Application +4 | -1
If 3a−2b+5c=03 a-2 b+5 c=0, family of the lines ax+by+c=0a x+b y+c=0 are always concurrent at a point whose coordinates are
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Correct option: B
(35,−25)\left(\frac{3}{5},-\frac{2}{5}\right)
Option B ((35,−25)\left(\frac{3}{5},-\frac{2}{5}\right)) is correct because the family of lines passes through the point that satisfies the given condition 3a−2b+5c=03a - 2b + 5c = 0.

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