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JEE MATHEMATICS MCQ: STRAIGHT LINES

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Application +4 | -1
The bisector of the acute angle formed between the lines 4x−3y+7=04x - 3y + 7 = 0 and 3x−4y+14=03x - 4y + 14 = 0 has the equation
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Correct option: C
x−y+3=0x - y + 3 = 0
Option C (x - y + 3 = 0) is correct because it represents the bisector of the acute angle between the two lines, determined by checking the sign.

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