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JEE PHYSICS MCQ: WORK-ENERGY-POWER

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Analyzing +4 | -1
Assertion: The gain in potential energy of an object of mass mm raised to height equal to the radius of earth is 12 mgR\frac{1}{2} \mathrm{~mgR}.
Reason: Kinetic energy at surface 12mv2=\frac{1}{2} m v^2= P.E at the top and at the top, v=gRv=\sqrt{g R}.

∴PE=12 mgR\therefore \mathrm{PE}=\frac{1}{2} \mathrm{~mgR}
View answer and explanation
Correct option: C
If assertion is true but reason is false
Option C is correct because the assertion is true, but the reason is false; the kinetic energy at the surface is not directly related to the potential energy at the top in this way.

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