The area of a $\triangle A B C$ is $a^2-(b-c)^2$. Then, $\tan A$ is equal to

JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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Application +4 | -1

The area of a

\triangle A B C

a^2-(b-c)^2

. Then,

\tan A

is equal to 

View answer and explanation

Correct option: C

\frac{8}{15}

Option C (

\frac{{8}}{{15}}

) is correct because by using the area formula and trigonometric identities, we can find the value of tan A.

Practice All Chapter MCQs →

{p_1},{p_2},{p_3}

\Delta \;ABC

A,B,C

\Delta

p_1^{ - 2} + p_2^{ - 2} + p_3^{ - 2}

5k,\;6k,\;5k

k

\Delta \,ABC

a = \left( {b - c} \right)\sec \theta

\frac{{2\,\sqrt {bc} }}{{b - c}}\,\,\sin \,\,\frac{A}{2} =

\Delta \;ABC,\frac{{b + c}}{a}

\Delta = {a^2} - {\left( {b - c} \right)^2}

\Delta

\Delta \;ABC

\tan A

A

2 s