Question

${\rm{\Lambda }}_{{\rm{ClC}}{{\rm{H}}_2}{\rm{COONa}}}^\infty = 224{\Omega ^{ - 1}}{\kern 1pt} {\kern 1pt}{\rm{c}}{{\rm{m}}^2}{\kern 1pt} {\kern 1pt}{\rm{g}}{\kern 1pt} {\kern 1pt} {\rm{equi}}{{\rm{v}}^{ - 1}}$ ${\rm{\Lambda }}_{NaCl}^\infty = 38.5{\Omega ^{ - 1}}{\kern 1pt} {\kern 1pt}{\rm{c}}{{\rm{m}}^2}{\kern 1pt} {\kern 1pt}{\rm{g}}{\kern 1pt} {\kern 1pt} {\rm{equi}}{{\rm{v}}^{ - 1}}$ ${\rm{\Lambda }}_{HCl}^\infty = 203{\Omega ^{ - 1}}{\kern 1pt} {\kern 1pt}{\rm{c}}{{\rm{m}}^2}{\kern 1pt} {\kern 1pt}{\rm{g}}{\kern 1pt} {\kern 1pt} {\rm{equi}}{{\rm{v}}^{ - 1}}$ What is the value of ${\lambda _{{\rm{ClC}}{{\rm{H}}_2}{\rm{COOH}}}} = ?$

Accepted Answer

$388.5{\Omega ^{ - 1}}{\kern 1pt} {\kern 1pt}{\rm{c}}{{\rm{m}}^2}{\kern 1pt} {\kern 1pt}{\rm{g}}{\kern 1pt} {\rm{equi}}{{\rm{v}}^{ - 1}}$

Answer

$288.5{\Omega ^{ - 1}}{\kern 1pt} {\kern 1pt}{\rm{c}}{{\rm{m}}^2}{\kern 1pt} {\kern 1pt}{\rm{g}}{\kern 1pt} {\kern 1pt} {\rm{equi}}{{\rm{v}}^{ - 1}}$

Answer

$289.5{\Omega ^{ - 1}}{\kern 1pt} {\kern 1pt}{\rm{c}}{{\rm{m}}^2}{\kern 1pt} {\kern 1pt}{\rm{g}}{\kern 1pt} {\kern 1pt} {\rm{equi}}{{\rm{v}}^{ - 1}}$

Answer

$59.5{\Omega ^{ - 1}}{\kern 1pt} {\kern 1pt}{\rm{c}}{{\rm{m}}^2}{\kern 1pt} {\kern 1pt}{\rm{g}}{\kern 1pt} {\kern 1pt} {\rm{equi}}{{\rm{v}}^{ - 1}}$

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