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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1
∫sin⁡(log⁡x)dx=\int \sin (\log x) d x=
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Correct option: C
12x[sin⁡(log⁡x)−cos⁡(log⁡x)]\frac{1}{2} x[\sin (\log x)-\cos (\log x)]
Option C (12x[sin⁡(log⁡x)−cos⁡(log⁡x)]\frac{1}{2} x[\sin (\log x)-\cos (\log x)]) is correct because it is the result of integrating sin⁡(log⁡x)\sin (\log x) using integration by parts twice.

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