JEE PHYSICS MCQ: THERMODYNAMICS

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Application +4 | -1

One mole of an ideal gas expands at a constant temperature of

300K

from an initial volume of

10\,\,\,litres

to a final volume of

20\,\,\,litres

. The work done in expanding the gas is

(R = 8.31J/mole - K)

View answer and explanation

Correct option: B

1728\,\,joules

Option B (

1728\,joules

) is correct because the work done in an isothermal expansion is calculated using the formula

{W_{iso}} = \mu RT{\log _e}\frac{{{V_2}}}{{{V_1}}}

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