JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

Let

R

be the set of real numbers and the mapping

f: R \rightarrow R

and

g: R \rightarrow R

be defined by

f(x)=5-x^2

and

g(x)=3 x-4

, then the value of

(f o g)(-1)

View answer and explanation

Correct option: A

-44

Option A (-44) is correct because it results from correctly evaluating the composite function

(f \circ g)(-1)

More Questions from FUNCTIONS

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f:(-\infty, 2] \longrightarrow(-\infty, 4]

f(x)=x(4-x)

f^{-1}(x)

g(f(x))=|\sin x|

f(g(x))=(\sin \sqrt{x})^2

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

f\left( x \right) = x - \left[ x \right]

{f^{ - 1}}\left( x \right)

f: R \rightarrow R

f(x)=x^4

f(x)=(x+1)^2-1(x \geq-1)

S=\left\{x: f(x)=f^{-1}(x)\right\}