JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1

\int e^x\left(\frac{1-\sin x}{1-\cos x}\right) d x

is equal to

View answer and explanation

Correct option: B

-e^x \cot (x / 2)

Option B is correct because the integral simplifies to

-e^x \cot(x/2) + c

by rewriting the integrand and recognizing the form

\int e^x [f(x) + f'(x)] dx = e^x f(x) + c

More Questions from INDEFINITE INTEGRATION

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\int \sin ^5 x \cos ^4 x d x=

f(x)

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f\left(\frac{4}{25}\right)

\int \frac{1-7 \cos ^2 x}{\sin ^7 x \cos ^2 x} d x=\frac{f(x)}{\sin ^7 x}+C

\int {e}^{{x}^2}\left(2-\frac{1}{{x}^2}\right) {de}={e}^{{x}^2} {f}({x})+{C}

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{C}

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