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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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The value of the integral ∫0πxsin⁡x1+cos⁡2xdx\int\limits_{0}^\pi \frac{x \sin x}{1+\cos ^2 x} d x is
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Correct option: B
π24\frac{\pi^2}{4}
Option B (π24\frac{\pi^2}{4}) is correct because using the property ∫0af(x)dx=∫0af(a−x)dx\int_0^a f(x) dx = \int_0^a f(a-x) dx and then substituting cos⁡x=t\cos x = t, we can evaluate the definite integral to get π24\frac{\pi^2}{4}.

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